|-||All stainless steel parts|
|Application||Air, non-hazardous liquids|
|Inlet pressure||0.1-1.0 MPa|
|Low pressure||0.05-0.9 MPa|
|Up to 90% of inlet pressure (gauge)|
|Min. differential pressure||0.05 MPa|
|Max. coeff. pressure reduction||20: 1|
|Operating temperature||5-80 ° C|
|Valve seat leaks||No|
|Material||Frame||Cast stainless steel|
|Valve||Stainless steel (NBR)|
|Valve seat||Stainless steel|
|Plunger, cylinder||Stainless steel|
|Compound||Flanged JIS 10K FF|
1. Parts of the flow path (GP-1000TSS) or all parts (GP-1000TAS) are made of stainless steel.
2. Zero seat leakage. High precision manufacturing of moving parts provides increased work efficiency.
3. Simple and reliable design of internal parts.
|Nominal size||L||H 1||H||The weight|
■ Dependence of the set pressure on the pneumatic load pressure
In the general case, the dependence of the setting pressure on the air pressure of the pneumatic load is as follows. The set pressure may vary slightly depending on the operating conditions. In this case, it is necessary to correct the pneumatic load pressure.
Find the intersection point between the inlet and reduced pressure values. If the intersection point is in zone (A), the outlet pressure is regulated. If the point of intersection is in zone (B), the valve is not suitable for the given operating conditions.
If the inlet pressure is greater than 0.7 MPa and the pressure reduction ratio is greater than 10: 1, the correction factor should be determined from the above graph and multiplied by the Cv value.
Choose a pressure reducing valve with an inlet pressure of 0.8 MPa and a reduced pressure of 0.05 MPa. Find the point of intersection (A) of the inlet pressure with the outlet pressure graph on the graph and draw a horizontal line from it to the intersection with the vertical axis.
The correction factor will be 0.85. For a nominal size of 25A, the corrected Cv value is determined by the formula: 4 (nominal Cv value) 0.85 (correction factor) = 3.4
GP-1000T Series Valve Selection Charts
This graph shows the dependence of the reduced pressure when the pressure at the valve inlet changes from 0.3 MPa to 1 MPa
at a set reduced pressure of 0.1 MPa.
Sizing charts (liquid: 20 ˚C, air)
When sizing the pressure reducing valve at inlet pressure (P1), outlet pressure (P2) and flow rates of 0.6 MPa, 0.4 MPa and 1,000 m3 / h, respectively (standard conditions), first find the intersection point (a ) pressure lines at the inlet 0.6 MPa and pressure at the outlet 0.4 MPa. From this point, draw a line down to the intersection (b) with a flow characteristic of 1000 m3 / h (standard conditions). Since the intersection point (B) lies between sizes 40A and 50A, the larger of the two, 50A, must be selected.
Selection of the nominal size of the pressure reducing valve: inlet pressure (P1) - 0.8 MPa, outlet pressure (P2) - 0.05 MPa, flow rate - 800 m3 / h (standard conditions). First you need to find the point of intersection (C) of the inlet pressure graph (P1) for 0.8 MPa with an oblique line. From this point, draw a line to the left until it intersects with the 0.05 MPa outlet pressure line at point (D). From point (D), draw a line down to the intersection (E) with a flow line of 800 m3 / h (standard conditions). Since the intersection point (E) is between dimensions 32A and 40A, choose the larger of the two, 40A. * The safety factor should be taken equal to 80-90%.
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